iz^2-(2i-2)z=4

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Solution for iz^2-(2i-2)z=4 equation:


Simplifying
iz2 + -1(2i + -2) * z = 4

Reorder the terms:
iz2 + -1(-2 + 2i) * z = 4

Reorder the terms for easier multiplication:
iz2 + -1z(-2 + 2i) = 4
iz2 + (-2 * -1z + 2i * -1z) = 4

Reorder the terms:
iz2 + (-2iz + 2z) = 4
iz2 + (-2iz + 2z) = 4

Reorder the terms:
-2iz + iz2 + 2z = 4

Solving
-2iz + iz2 + 2z = 4

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-2iz + iz2 + 2z + -2z = 4 + -2z

Combine like terms: 2z + -2z = 0
-2iz + iz2 + 0 = 4 + -2z
-2iz + iz2 = 4 + -2z

Reorder the terms:
-4 + -2iz + iz2 + 2z = 4 + -2z + -4 + 2z

Reorder the terms:
-4 + -2iz + iz2 + 2z = 4 + -4 + -2z + 2z

Combine like terms: 4 + -4 = 0
-4 + -2iz + iz2 + 2z = 0 + -2z + 2z
-4 + -2iz + iz2 + 2z = -2z + 2z

Combine like terms: -2z + 2z = 0
-4 + -2iz + iz2 + 2z = 0

The solution to this equation could not be determined.

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